82(0.083=x)^2=4x^2

Solution for 82(0.083=x)^2=4x^2 equation:

82(0.083=x)^2=4x^2

We move all terms to the left:

82(0.083-(x)^2)=0

We multiply parentheses

-82x^2+6.806=0

a = -82; b = 0; c = +6.806;
Δ = b2-4ac
Δ = 02-4·(-82)·6.806
Δ = 2232.368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2232.368}}{2*-82}=\frac{0-\sqrt{2232.368}}{-164}
=-\frac{\sqrt{}}{-164}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2232.368}}{2*-82}=\frac{0+\sqrt{2232.368}}{-164}
=\frac{\sqrt{}}{-164}
$